The invention relates to a process for preparing 5-(α-haloacetyl)-8-substituted oxy-(1H)-quinolin-2-ones. The process involves (i) reacting (a) 8-hydroxy-(1H)-quinolin-2-one with an acylating agent and a Lewis acid to form 5-acetyl-8-hydroxy-(1H)-quinolin-2-one; or (b) 8-hydroxy-(lH)-quinolin-2-one with an acylating agent to form 8-acetoxy-(lH)-quinolin-2-one, and treating, in-situ, the 8-acetoxy-(1H)-quinolin-2-one with a Lewis acid to form 5-acetyl-8-hydroxy-(1H)-quinolin-2-one; or (c) 8-acetoxy-(1H)-quinolin-2-one with a Lewis acid to form 5-acetyl-8-hydroxy-(lH)-quinolin-2-one; (ii) reacting the 5-acetyl-8-hydroxy-(1H)-quinolin-2-one prepared in Step (i) with a compound having the Formula RL in the presence of a base and a solvent to form 5-acetyl-8-substituted oxy-(1H)-quinolin-2-one, wherein R is a protecting group and L is a leaving group; and (iii) reacting the 5-acetyl-8-substituted oxy-(1H)-quinolin-2-one with a halogenating agent in the presence of a solvent to form a 5-(α-haloacetyl)-8-substituted oxy-(1H)-quinolin-2-one.
该发明涉及一种制备5-(α-卤代乙酰基)-8-取代氧基-(1H)-
喹啉-2-酮的过程。该过程包括:(i) 与酰化试剂和Lewis酸反应,将(a)8-羟基-(1H)-
喹啉-2-酮形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;或(b)8-羟基-(1H)-
喹啉-2-酮与酰化试剂反应形成8-乙酰氧基-(1H)-
喹啉-2-酮,并在原位处理8-乙酰氧基-(1H)-
喹啉-2-酮与Lewis酸反应形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;或(c)8-乙酰氧基-(1H)-
喹啉-2-酮与Lewis酸反应形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;(ii) 在碱和溶剂的存在下,将步骤(i)中制备的5-乙酰基-8-羟基-(1H)-
喹啉-2-酮与具有RL式的化合物反应,形成5-乙酰基-8-取代氧基-(1H)-
喹啉-2-酮,其中R是保护基,L是离去基;(iii) 在溶剂的存在下,将5-乙酰基-8-取代氧基-(1H)-
喹啉-2-酮与卤代试剂反应,形成5-(α-卤代乙酰基)-8-取代氧基-(1H)-
喹啉-2-酮。