16β-ent-17-Kauranol (1a), the corresponding C-19 ester (1b), and 16β,17-phyllocladanol (2), on reaction with lead tetraacetate – iodine in refluxing cyclohexane, suffered intramolecular attack mainly at C-11. Thus1a gave as major products the 11-en-17-ol (3a) and the 11β-iodo-12β,17-ether (4a), along with minor amounts of the 9,11-en-12β,17-ether (5), the 11β,17-ether (6a), and, resulting from attack at C-12, the 12β,17-ether (7). The phyllocladanol 2 gave the 11β,17-ether (8) and the 9,11-en-12β,17-ether (9). The assignment of structures 6a, 7, and 8 to the ethers rests on their conversion with ruthenium tetroxide into the corresponding lactones, 10, 11, and 12.
在回流环己烷中,16β-ent-17-Kauranol(1a)、相应的C-19酯(1b)和16β,17-Phyllocladanol(2)与四乙酸铅-碘反应,主要发生在C-11的分子内攻击。因此,1a主要产生11-烯-17-醇(3a)和11β-碘-12β,17-醚(4a),以及少量的9,11-烯-12β,17-醚(5)、11β,17-醚(6a)和由于在C-12处发生攻击而产生的12β,17-醚(7)。Phyllocladanol 2生成了11β,17-醚(8)和9,11-烯-12β,17-醚(9)。将结构6a、7和8归因于它们与四氧化二铑的转化为相应的内酯,即10、11和12。