Reaction of Cp2TiCl2 (Cp = η5-C5H5) with sodium 3,6-di-tert-butylcatecholate (Na2Cat36) leads to mononuclear complex [Cp2TiCat36], while the isomeric sodium 3,5-di-tert-butylcatecholate (Na2Cat35) gives the mixed-valence binuclear complex [Cp2Ti(μ-Cat35)2TiCp]. The latter was characterized by EPR spectroscopy and magnetic susceptibility measurements, and shown to be a Ti-centred radical. DFT calculations
CP的反应2的TiCl 2(CP =η 5 -C 5 H ^ 5)与
钠3,6-二-叔-butylcatecholate(
钠2猫36)导致单核配合物的[CP 2 TiCat 36 ],而异构
钠3 ,5-二-叔-butylcatecholate(
钠2猫35)给出了混合价双核配合物的[CP 2的Ti(μ-猫35)2TiCP]。后者通过EPR光谱学和磁化率测量来表征,并显示为以Ti为中心的自由基。DFT计算证实未成对的电子位于TiCP 2片段的Ti原子上。