A Novel, Readily Accessible Lactosaminyl Donor:<i>N</i>-Trichloroethoxycarbonyl-hexa-<i>O</i>-benzoyl-<i>β</i>-D-lactosaminyl Fluoride
作者:Eisuke Kaji、Frieder W. Lichtenthaler、Yumiko Osa、Shonosuke Zen
DOI:10.1246/bcsj.68.1172
日期:1995.4
A simple, preparatively satisfactory 10-step sequence is described for converting lactose into a novel, suitably blocked lactosaminyl donor: N-Trichloroethoxycarbonyl-β-d-lactosaminyl fluoride (5). The key intermediate in this conversion is the particularly well-accessible oxime of lactosulosyl bromide (52% for the 6 steps from lactose), which on α-glycosidation with p-methoxybenzyl alcohol, oxime reduction, N-protection by Troc chloride, and the anomeric fluorination yields 5 (37% for the 4 steps). The utility of 5 as an effective donor was proved by the β-selective glycosylation of the primary 6-OH of 1,2 : 3,4-di-O-isopropylidene-α-d-galactopyranose (14) and the 3-OH of methyl 2,4,6-tri-O-benzyl-β-d-galactopyranoside (16), both affording the respective trisaccharides 15 and 18 in high yields. The latter, when subjected to N-deprotection, N-acetylation, and de-O-acylation gave, in 42% yield based on donor 5, β-d-Gal-(1→4)-β-d-GlcNAc-(1→3)-β-d-Gal-(1→Me, a core trisaccharide unit of immunologically important carbohydrate antigens.
本文描述了一种简单、制备令人满意的 10 步序列,用于将乳糖转化为一种新型的、适当封端的乳糖胺基供体:N-Trichloroethoxycarbonyl-β-d-lactosaminyl fluoride (5)。这种转化的关键中间体是特别容易获得的溴化乳糖基肟(从乳糖开始的 6 个步骤中占 52%),在与对甲氧基苄醇进行α-糖苷化、肟还原、三氯乙烷的 N 保护和异构体氟化后,可得到 5(4 个步骤中占 37%)。1,2 : 3,4-二-O-异亚丙基-α-d-吡喃半乳糖的初级 6-OH(14)和甲基 2,4,6-三-O-苄基-β-d-吡喃半乳糖苷的 3-OH(16)的β-选择性糖基化证明了 5 是一种有效的供体,两者都能以高产率得到相应的三糖 15 和 18。后者经过 N-脱保护、N-乙酰化和去 O-乙酰化后,以 42% 的产率(基于供体 5)得到了β-d-Gal-(1→4)-β-d-GlcNAc-(1→3)-β-d-Gal-(1→Me),这是免疫学上重要的碳水化合物抗原的核心三糖单元。