作者:V.K. Jain、R. Bohra、R.C. Mehrotra
DOI:10.1016/s0022-328x(00)94363-8
日期:1980.1
Ph3SbBr2 reacts with Na[RCOCHCOR′] to form compounds of the type Ph3SbBr(RCOCHCOR′) (where R = R′ = CH3, C(CH3)3 and R ɳ R′ = CH3, C6H5; CH3, 4′-MeC6H4; CH3, 4′-MeOC6H4; CH3, 4′-ClC6H4; CH3, 4′BrC6H4 and CF3, 2-C4H3S). Reactions of Ph3Sb(OMe)2 with RCOCH2COR′ yield Ph3Sb(OMe) (RCOCHCOR′). From molecular weight, IR and NMR data, it is concluded that 1,3-diketone ligand moiety behaves as a bidentate
Ph 3 SbBr 2与Na [RCOCHCOR']反应形成Ph 3 SbBr(RCOCHCOR')类型的化合物(其中R = R'= CH 3,C(CH 3)3,RɳR'= CH 3,C 6 ħ 5 ; CH 3,4'-MEC 6 ħ 4 ; CH 3,4'-MeOC 6 H ^ 4 ; CH 3,4'-CLC 6 ħ 4 ; CH 3,4'BrC 6 ħ 4和CF 3, 2-C 4高3S)。Ph 3 Sb(OMe)2与RCOCH 2 COR'的反应产生Ph 3 Sb(OMe)(RCOCHCOR')。从分子量,IR和NMR数据可以得出结论,在这些配合物中1,3-二酮配体部分表现为二齿配体。讨论了包含对称和不对称配体的配合物的立体化学。