Chromatographic analysis on silicic acid of the so-called "tri-O-tosylsucrose" which is formed in 95% yield on the reaction of 3 moles of p-toluenesulphonyl chloride with 1 mole of sucrose in pyridine at 0° has shown the substance to contain penta-, tetra-, tri-, and di-O-tosylsucroses in the molar ratios 0.05:0.33:1:1, respectively. Any mono-O-tosylsucrose present in the reaction mixture may have been lost in the isolation of the product. The composition of the product was substantially the same when the reaction was performed at −18°. The chromatogram separated the tritosylates into two subfractions. The major subfraction represented 29% by weight of the original "tri-O-tosylsucrose" and could be converted to 1′,2:3,6:3′,6′-trianhydrosucrose in 77.4% yield. Therefore, the so-called "tri-O-tosylsucrose" can contain only 25–29% of 1′,6,6′-tri-O-tosylsucrose. 6,6′-Di-O-tosylsucrose crystallized from the di-O-tosylsucrose fraction in 10% over-all yield.
在0度下,通过在
吡啶中使用3摩尔
对甲苯磺酰氯和1摩尔
蔗糖反应,可以得到所谓的“三-O-对
甲苯磺酰基
蔗糖”,产率为95%。对这种
硅酸分离物进行
色谱分析,结果显示其含有五、四、三和二个-O-对
甲苯磺酰基
蔗糖,摩尔比分别为0.05:0.33:1:1。在分离产物时,任何存在于反应混合物中的单-O-对
甲苯磺酰基
蔗糖可能已经丢失。当在-18度下进行反应时,产物的组成基本相同。色谱图将三
磺酸酯分离成两个亚分。主要亚分在“三-O-对
甲苯磺酰基
蔗糖”的原重量中占29%,可以转化为1′,2:3,6:3′,6′-三脱
水蔗糖,收率为77.4%。因此,所谓的“三-O-对
甲苯磺酰基
蔗糖”只能含有25-29%的1′,6,6′-三-O-对
甲苯磺酰基
蔗糖。6,6′-二-O-对
甲苯磺酰基
蔗糖从二-O-对
甲苯磺酰基
蔗糖分离物中结晶,总收率为10%。