The iridium complex [IrCl(COD)]2 reacts with diphenylphosphinoacetic acid (1) in the presence of CO to afford the iridium(III) complex IrHCl(CO)(η2-Ph2PCH2CO2)(η1-Ph2PCH2CO2H) (3) which in the solid state exists as a hydrogen-bonded dimer. Complex 3 converts to IrH(CO)(η2-Ph2PCH2CO2)2 (4) when treated with AgO3SCF3 in dichloromethane. The tertiary phosphine PPh2(Ph-2,6-Me2) (2) reacts with solutions
铱络合物[的IrCl(COD)] 2种发生反应与diphenylphosphinoacetic酸(1在CO存在,得到
铱(III)络合物IrHCl(CO))(η 2 -Ph 2 PCH 2 CO 2)(η 1 -Ph以氢键结合的二聚体的形式存在的2 PCH 2 CO 2 H)(3)。复杂3个转换到IRH(CO)(η 2 -Ph 2 PCH 2 CO 2)2(4当用处理过的AgO)3 SCF 3在
二氯甲烷中。叔膦PPh 2(Ph-2,6-Me 2)(2)与[RhCl(CO)2 ] 2和[IrCl(COD)] 2的溶液(在CO存在下)反应,在
二氯甲烷中正方形平面络合物MCl(CO)[PPh 2(Ph-2,6-Me 2)] 2(M = Rh(5)或Ir(6))高产率。
铱(I)配合物6与HgCl 2发生氧化加成反应,生成配合物IrCl 2(HgCl)(CO)[PPh 2(Ph-2,6-Me 2)] 2(7),配合物5对该试剂无反应。