作者:A.J. Lundeen、A.C. Oehlschlager
DOI:10.1016/s0022-328x(00)87832-8
日期:1970.12
as major products (after hydrolyses) substituted neopentyl alcohols. Triethylaluminum and propylene oxide react (mole ratio >1) forming 2-methylbutanol in high (ca. 98%) yield. The products of this reaction are dependent on the mole ratio of reactants. When the ratio (triethylaluminum/propylene oxide) is 0.7, 2-pentanol is the major product.The products of reaction with cis- and trans-2,3-epoxybutane
三乙基铝和1,1-二烷基环氧乙烷的主要产物(水解后)为取代的新戊醇。三乙基铝和环氧丙烷反应(摩尔比> 1)以高产率(约98%)形成2-甲基丁醇。该反应的产物取决于反应物的摩尔比。当三乙基铝/环氧丙烷的比率为0.7时,主要是2-戊醇。与顺式-和反式-2,3-环氧丁烷的反应产物(三乙基铝/环氧的摩尔比> 1)是苏基-3-甲基-2-戊醇和赤型-3-甲基-2-戊醇分别表明在接受乙基的碳上已经发生了转化。讨论了这些反应的机理。