The reaction of [Ru(η 6-cymene)Cl2]2 and PPh2Cl in the ratio 1:2 gives a stable [Ru(η 6-cymene) Cl2(PPh2Cl)] complex. Attempts to make the cationic [Ru(η 6-cymene)Cl(PPh2Cl)2]Cl with excess PPh2Cl and higher temperatures led to adventitious hydrolysis and formation of [Ru(η 6-cymene)Cl2(PPh2OH)]. Attempts to make a phosphinite complex by reacting [Ru(η 6-cymene)Cl2]2 with PPh2Cl in the presence of an alcohol results in the reduction of PPh2Cl to give [Ru(η 6-cymene)Cl2(PPh2H)] and the expected phosphinite. The yield of the hydride complex is highest when the alcohol is 1-phenyl-ethane-1,2-diol. All three half-sandwich complexes are characterized by X-ray crystallography. Surprisingly, the conversion of chlorodiphenylphosphine to diphenylphosphine is mediated by 1-phenyl-ethane-1,2-diol even in the absence of the ruthenium half-sandwich precursor.
Ru(η 6-
氰基)Cl2]2和PPh2Cl以1:2的比例反应生成稳定的[Ru(η 6-
氰基)Cl2(PPh2Cl)]络合物。尝试用过量的 PPh2Cl 和更高的温度来制造阳离子 [Ru(η-6-亚甲基)Cl(PPh2Cl)2]Cl,会导致偶然的
水解并形成 [Ru(η-6-亚甲基)Cl2(PPh2OH)]。试图通过[Ru(η 6-亚甲基)Cl2]2 与 PPh2Cl 在醇的存在下反应来制造膦络合物,结果 PPh2Cl 被还原,生成[Ru(η 6-亚甲基)Cl2(PPh2H)]和预期的膦。当醇为 1-苯基-1,2-
乙二醇时,
氢化物络合物的产率最高。所有这三种半夹心复合物都具有 X 射线晶体学特征。令人惊讶的是,即使在没有
钌半三明治前体的情况下,
氯二苯基膦向
二苯基膦的转化也是由 1-苯基-1,2-
乙二醇介导的。