γ-picoline, or 3,5-lutidine, leads to [Ni(C 6 Cl 5 )L 3 ]ClO 4 . The formation of the new ionic organometallic compounds depends on its insolubility; thus, the reaction in acetone leads to [Ni(C 6 Cl 5 )py 2 (PPh 3 )]ClO 4 , insoluble in that solvent. The action of potassium salts (KX) or phosphines (PR 3 ) on the ionic compounds gives [NiX(C 6 Cl 5 )L 2 ] (X = Cl, Br, NO 2 , C 6 Cl 5 O and NCS), and
摘要在过量
吡啶,β-
甲基吡啶,γ-
甲基吡啶或3,5-二
甲基吡啶存在下,向[NiCl(C 6 Cl 5)(PPh 3)2]的苯溶液中添加过量的NaClO 4,导致生成[Ni(C 6 Cl 5)L 3] ClO 4。新的离子有机
金属化合物的形成取决于它的不溶性。因此,在
丙酮中的反应导致不溶于该溶剂的[Ni(C 6 Cl 5)py 2(PPh 3)] ClO 4。
钾盐(KX)或膦(PR 3)对离子化合物的作用产生[NiX(C 6 Cl 5)L 2](X = Cl,Br,NO 2,C 6 Cl 5 O和
NCS),并且[Ni(C 6 Cl 5)py(PR 3)2] ClO 4 [R = Ph和Et)。通过在[NiX(C 6 Cl 5)py 2]中用膦部分或全部取代胺,形成络合物[NiCl(C 6 Cl 5)py(PEt 3)]和[Ni(NO 2)(C 6 Cl 5) )(PPh 3)2]。