作者:Seiji Shinkai、Sayuri Kawanabe、Akito Kawase、Toshiro Yamaguchi、Osamu Manabe、Shigeharu Harada、Hideki Nakamura、Nobutami Kasai
DOI:10.1246/bcsj.61.2095
日期:1988.6
In order to assess the effect of intramolecular acid catalysis on the specific flavin reactivities, 3-methyl-10-(2-hydroxyphenyl)isoalloxazine (1(2OH)) and 3-methyl-10-(2-hydroxy-1-naphthyl)isoalloxazine (2(2OH)) were synthesized and the redox properties were compared with those of reference flavins such as 3-methyl-10-(2-methoxyphenyl)isoalloxazine (1(2OMe)) and 3-methyl-10-(2-methoxy-1-naphthyl)isoalloxazine (2(2OMe)). The pKa values for 1(2OH) and 2(2OH) were determined to be 7.7 and 7.0, respectively, which were lower than that of 3-methyl-10-(4-hydroxyphenyl)isoalloxazine (1(4OH): pKa 8.6). It is thus unlikely that 2′-OH and N(1) form a hydrogen bond at the initial state of the reaction (i.e., at the oxidized state). The X-ray crystallographic studies indicated that the phenyl ring makes an angle of 79.7° with the isoalloxazine ring and the 2′-OH group forms a hydrogen bond with methanol included in the crystal lattice. In acetonitrile at 30 °C 1-benzyl-1,4-dihydronicotinamide was not oxidized by 1(2OMe), 1(4OH), and 2(2OMe). On the other hand, the oxidation took place with 1(2OH) and 2(2OH) which have an acidic OH group at the 2′-position of the 10-aryl substituent. The presence of the intramolecular acid catalysis suggests that 2′-OH and N(1) can interact at least at the transition state or at the final state of the reaction (i.e., at the reduced state). In general, the oxidized flavin adopts a “planar” structure which is sterically tense while the reduced flavin adopts a “bent” structure which is sterically relaxed. As the structure of the transition state is more or less similar to the reduced form, the hydrogen-bonding interaction could increase on going from the tense initial state to the relaxed transition state. This is a novel example for acid catalysis in flavin-mediated reactions.
为了评估分子内酸催化对特定黄素反应性的影响,合成了3-甲基-10-(2-羟基苯基)异黄素(1(2OH))和3-甲基-10-(2-羟基-1-萘基)异黄素(2(2OH)),并将其氧化还原性质与参考黄素如3-甲基-10-(2-甲氧基苯基)异黄素(1(2OMe))和3-甲基-10-(2-甲氧基-1-萘基)异黄素(2(2OMe))进行了比较。1(2OH)和2(2OH)的pKa值分别为7.7和7.0,均低于3-甲基-10-(4-羟基苯基)异黄素(1(4OH):pKa 8.6)。因此,在反应的初始状态(即氧化状态)下,2′-OH和N(1)形成氢键的可能性较小。X射线晶体学研究表明,苯环与异黄素环之间的夹角为79.7°,而2′-OH基团与晶体格中包含的甲醇形成氢键。在30 °C的乙腈中,1-苯基-1,4-二氢烟酰胺未被1(2OMe)、1(4OH)和2(2OMe)氧化。另一方面,1(2OH)和2(2OH)(在10-芳基取代基的2′位置具有酸性OH基团)发生了氧化。分子内酸催化的存在表明,2′-OH和N(1)至少可以在反应的过渡态或最终状态(即还原状态)下相互作用。一般来说,氧化的黄素采用“平面”结构,立体张力较大,而还原的黄素则采用“弯曲”结构,立体张力较小。由于过渡态的结构或多或少与还原形式相似,因此在从紧张的初始状态转变为放松的过渡状态时,氢键相互作用可能会增强。这是黄素介导反应中酸催化的新颖例子。