The current invention describes a method for selecting a particular population of women having a risk of developing obstetric or gynecologic pathologies indicated as odds ratio (OR) value higher than 5.5, comprising the following steps in order:
a) determination of the levels of sialidase by means of the procedure described in Cauci et al. Am J Obstet Gynecol 1998; 178; 511-5 and/or prolidase activity by means of the procedure described in Cauci et al. J Infect Dis 1998; 178; 1698-706 in samples of body fluid;
b) determination of the pH value of said body fluid samples;
c) selecting the samples having a sialidase value equal or above 5.0 nmol of methoxyphenol and/or a prolidase level equal or above 1500 mOD for prolidase and a pH ≥ 5.0.
Consequently, this method gives the physician an efficient tool to decide whether or not to administer a pharmacological therapy to women at risk of severe adverse outcomes.
本发明描述了一种选择特定妇女群体的方法,这些妇女患产科或妇科疾病的风险表示为几率比(OR)值高于5.5,该方法依次包括以下步骤:
a) 通过 Cauci 等人,Am J Obstet Gynecol 1998; 178; 511-5 和/或 Cauci 等人,J Infect Dis 1998; 178; 1698-706 中描述的程序,测定体液样本中的
葡萄糖苷酶
水平;
b) 确定所述体液样本的 pH 值;
c) 挑选出
硅糖苷酶值等于或高于 5.0 毫摩尔
甲氧基苯酚和/或脯
氨酸酶
水平等于或高于 1500 毫摩尔脯
氨酸酶且 pH 值≥5.0 的样本。
因此,这种方法为医生提供了一个有效的工具,以决定是否对有可能出现严重不良后果的妇女进行药物治疗。