A process for the synthesis, in liquid phase and by fragments, of hGRF 1-44 and hGRF 1-40. This process consists in coupling, one after the other and in the order of the sequence of the GRF, (1) on the one hand, the following fragments: __________________________________________________________________________ H--Ala--Arg--Ala--Arg--Leu--NH.sub.2 called Fragment A hGRF (40-44) or alaninamide (40) H--Gln--Glu--Arg--Gly--OH called Fragment B'.sub.1 hGRF (36-39) H--Glu--Ser--Asn--OH called Fragment B'.sub.2 hGRF (33-35) H--Ser--Arg--Gln--Gln--Gly--OH called Fragment C hGRF (28-32) H--Leu--Gln--Asp--Ile--Met--OH called Fragment D' hGRF (23-27) H--Arg--Lys--Leu--OH called Fragment E'.sub.1 hGRF (20-22) __________________________________________________________________________ PAL to obtain the peptide K.sub.1 [(hGRF (20-44)] on the corresponding peptide having the sequence (20-40) and PA1 (2) on the other hand, the following fragments: __________________________________________________________________________ H--Gln--Leu--Ser--Ala called Fragment F.sub.1 hGRF (16-19) H--Tyr--Arg--Lys--Val--Leu--Gly OH called Fragment G.sub.1 hGRF (10-15) H--Ile--Phe--Thr--Asn--Ser--OH called Fragment H.sub.1 hGRF (5-9) __________________________________________________________________________ PAL to obtain the peptide J [hGRF (5-19)] and thereafter to couple together the peptides J and K.sub.1 in order to form the peptide having the sequence hGRF (5-44) or hGRF (5-40) and finally to couple the resulting peptide with the peptide H-Tyr-Ala-Asp-Ala-OH, called fragment I hGRF (1-4).
一种在液相中通过片段合成hGRF 1-44和hGRF 1-40的过程。该过程包括按照GRF序列的顺序依次耦合以下片段:__________________________________________________________________________ H-阿拉-精-阿拉-精-亮-NH.sub.2,称为片段A hGRF(40-44)或alaninamide(40) H-谷-谷-精-甘-OH,称为片段B'.sub.1 hGRF(36-39) H-谷-丝-
天冬氨酸-OH,称为片段B'.sub.2 hGRF(33-35) H-丝-精-谷-谷-甘-OH,称为片段C hGRF(28-32) H-亮-谷-
天冬氨酸-异亮-甲
硫氨酸-OH,称为片段D' hGRF(23-27) H-精-赖-亮-OH,称为片段E'.sub.1 hGRF(20-22) __________________________________________________________________________ 从相应的具有序列(20-40)的肽K.sub.1 [(hGRF(20-44))]和PA1中获得肽J [hGRF(5-19)]的片段。然后将肽J和K.sub.1耦合在一起,以形成具有序列hGRF(5-44)或hGRF(5-40)的肽,最后将所得肽与片段H-Tyr-Ala-Asp-Ala-OH耦合,称为片段I hGRF(1-4)。