Abstract The treatment of 2-(trifluoromethyl)aniline with 2,6-dimethylphenylmagnesium bromide yields 1-methyl-9-(2,6-dimethylphenyl)acridine by the formal reaction of one equivalent of the aniline and two equivalents of the Grignard reagent. Interestingly, one of the methyl groups is eliminated during the reaction, and the product contains three methyl groups only. In a similar way, the reaction of
摘要
2-(三氟甲基)苯胺用
2,6-二甲基苯基溴化镁处理,1-甲基-9-(2,6-二甲基苯基)
吖啶通过1当量
苯胺和2当量
格氏试剂的形式反应生成。有趣的是,其中一个甲基在反应过程中被消除,产物仅包含三个甲基。以类似的方式,
2-(三氟甲基)苯胺与2-乙基
苯基溴化镁的反应提供不含一个乙基的9-(2-
乙基苯基)
吖啶。机制进行了讨论。