Thermal reaction of [Ir(Me)(H)η2-Me2Si(CH2)2PPh2}(PMe3)2] with SiRH3 (R = n-butyl, pentyl or hexyl) resulted in silicon–carbon bond formation to give SiR(Me)H2 and [IrH2η2-Me2Si(CH2)2PPh2}(PMe3)2]. Isolation of Si(n-C6H13)MeH2 was achieved by preparative gas chromatography.
[Ir(Me)(H)η2-Me2Si(
CH2)2PPh2}(PMe3)2]与 SiRH3(R = 正丁基、戊基或己基)发生热反应,形成
硅碳键,得到 SiR(Me)H2 和 [IrH2η2-Me2Si( )2PPh2}(PMe3)2]。Si(n-
C6H13)MeH2 是通过制备气相色谱法分离出来的。