The invention relates to a process for preparing 5-(α-haloacetyl)-8-substituted oxy-(1H)-quinolin-2-ones. The process involves (i) reacting (a) 8-hydroxy-(1H)-quinolin-2-one with an acylating agent and a Lewis acid to form 5-acetyl-8-hydroxy-(1H)-quinolin-2-one; or (b) 8-hydroxy-(1H)-quinolin-2-one with an acylating agent to form 8-acetoxy-(1H)-quinolin-2-one, and treating, in-situ, the 8-acetoxy-(1H)-quinolin-2-one with a Lewis acid to form 5-acetyl-8-hydroxy-(1H)-quinolin-2-one; or (c) 8-acetoxy-(1H)-quinolin-2-one with a Lewis acid to form 5-acetyl-8-hydroxy-(1H)-quinolin-2-one; (ii) reacting the 5-acetyl-8-hydroxy-(1H)-quinolin-2-one prepared in Step (i) with a compound having the Formula RL in the presence of a base and a solvent to form 5-acetyl-8-substituted oxy-(1H)-quinolin-2-one, wherein R is a protecting group and L is a leaving group; and (iii) reacting the 5-acetyl-8-substituted oxy-(1H)-quinolin-2-one with a halogenating agent in the presence of a solvent to form a 5-(α-haloacetyl)-8-substituted oxy-(1H)-quinolin-2-one.
                            本发明涉及一种制备5-(α-卤代乙酰基)-8-取代氧基-(1H)-
喹啉-2-酮的过程。该过程包括:(i)将8-羟基-(1H)-
喹啉-2-酮与酰化剂和Lewis酸反应,形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;或将8-羟基-(1H)-
喹啉-2-酮与酰化剂反应,形成8-乙酰氧基-(1H)-
喹啉-2-酮,然后在原位处理8-乙酰氧基-(1H)-
喹啉-2-酮与Lewis酸反应,形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;或将8-乙酰氧基-(1H)-
喹啉-2-酮与Lewis酸反应,形成5-乙酰基-8-羟基-(1H)-
喹啉-2-酮;(ii)将步骤(i)中制备的5-乙酰基-8-羟基-(1H)-
喹啉-2-酮与具有RL式的化合物在碱和溶剂的存在下反应,形成5-乙酰基-8-取代氧基-(1H)-
喹啉-2-酮,其中R是保护基,L是离去基;(iii)将5-乙酰基-8-取代氧基-(1H)-
喹啉-2-酮与卤代试剂在溶剂的存在下反应,形成5-(α-卤代乙酰基)-8-取代氧基-(1H)-
喹啉-2-酮。