Oxidation of organometallic compounds (RM, M=Li, MgBr, ZnBr, CuCNLi, Cu(R)CNLi2) with tBuOOLi, Ti(OiPr)4- mediated with tBuOOH, and with O2, to give alcohols (ROH). Are radicals R involved?
作者:Michael Möller、Marc Husemann、Gernot Boche
DOI:10.1016/s0022-328x(00)00596-9
日期:2001.4
with dioxygen O2 (method C) occur with loss of stereochemistry in the cyclopropyl alcohols ROH (RM, M=Li, MgBr), and additional formation of cyclopropyl dimers R–R 3 in the case of RM, M=Cu(CN)Li, CuR(CN)Li2. This is due to facile electron transfer from RM to O2 and fast isomerization (dimerization) of the intermediate radicals R. The high tendency of RM cuprates, M=Cu(CN)Li, CuR(CN)Li2, for electron
有机金属化合物(RM,M = Li,MgBr,ZnBr,Cu(CN)Li,CuR(CN)Li 2)用t BuOOLi(或PhCMe 2 OOLi)(方法A)氧化为相应的醇(ROH),好到非常好的产量。在RM,M = Li,MgBr和ZnBr的情况下,这种氧化作用也与质子体系Ti(O i Pr)4 + t BuOOH(方法B)一起很好地起作用。立体化学的研究与结构稳定的顺-和反式-环丙基金属化合物,顺式-和反式- 1 -M,分别表明的RM,M =锂,MgBr,反应用吨BuOOLi(方法A)和Ti(O i Pr)4 + t BuOOH(方法B)遵循亲核试剂RM的S N 2型途径,位于t BuOOLi(TiX 3)的亲电子氧原子上(尽管是阴离子!)给出具有在R处的构型保留的ROM(分离为酯2)。相反,在环丙基醇ROH(RM,M = Li,MgBr)中失去了立体化学的情况下,发生了双氧O 2(方法C)的氧化。在RM,M