beta-bromo alcohols can be transformed directly to ketones in very good yields by a free radical process. Tertiary beta-bromo alcohols do not react while the primary ones are transformed to aldehydes in lower yields. The reaction involves an abstraction of a hydrogen atom alpha to an OH group, followed by elimination of the bromine atom and subsequent tautomerization of an enol to a ketone.
β-
溴代仲醇可以通过自由基过程直接以非常好的收率转化为酮。β-
溴叔醇不反应,而伯-
溴醇则以较低的产率转化为醛。该反应包括将氢原子α抽象为OH基,然后消除
溴原子,随后将烯醇互变异构为酮。