Magnetic superexchange interactions: trinuclear bis(oxamidato) versus bis(oxamato) type complexes
作者:Mohammad A. Abdulmalic、Azar Aliabadi、Andreas Petr、Yulia Krupskaya、Vladislav Kataev、Bernd Büchner、Ruslan Zaripov、Evgeniya Vavilova、Violeta Voronkova、Kev Salikov、Torsten Hahn、Jens Kortus、Francois Eya'ane Meva、Dieter Schaarschmidt、Tobias Rüffer
DOI:10.1039/c4dt03579h
日期:——
(opboH4R2, R = Me 1, Et 2, nPr 3) in good yields. Treatment of 1–3 with half an equivalent of [Cu2(AcO)4(H2O)2] or one equivalent of [Ni(AcO)2(H2O)4] followed by the addition of four equivalents of [nBu4N]OH resulted in the formation of mononuclear bis(oxamidato) type complexes [nBu4N]2[M(opboR2)] (M = Ni, R = Me 4, Et 5, nPr 6; M = Cu, R = Me 7, Et 8, nPr 9). By addition of two equivalents of [Cu(pmdta)(NO3)2]
用过量的RNH 2在MeOH中的溶液处理邻苯二甲双(草酰胺酸)(opbaH 2 Et 2)的二乙酯,以排他地形成相应的邻苯二甲双(N(R)-草酰胺)(opboH 4 R 2,R = Me 1,Et 2,n Pr 3),产率高。用一半当量的[Cu 2(AcO)4(H 2 O)2 ]或一当量的[Ni(AcO)2(H 2 O)4来处理1-3],然后加入四当量的[ n Bu 4 N] OH,导致形成单核双(oxamidato)型复合物[ n Bu 4 N] 2 [M(opboR 2)](M = Ni,R = Me 4,Et 5,n Pr 6; M = Cu,R = Me 7,Et 8,n Pr 9)。通过在7-9的MeCN溶液中添加两当量的[Cu(pmdta)(NO 3)2 ] ,新型三核配合物[Cu 3(opboR 2)(L)2可以得到](NO 3)2(L = pmdta,R = Me 10,Et