Chemistry of Iridium(I) Cyclooctadiene Compounds with Thiapentadienyl, Sulfinylpentadienyl, and Butadienesulfonyl Ligands
作者:Procoro Gamero-Melo、Patricia Andrea Melo-Trejo、Marisol Cervantes-Vasquez、Nelly Paola Mendizabal-Navarro、Brenda Paz-Michel、Tere Isabel Villar-Masetto、Miguel Angel Gonzalez-Fuentes、M. Angeles Paz-Sandoval
DOI:10.1021/om2007166
日期:2012.1.9
the dinuclear asymmetric structure of 12 remains in CDCl3. The series of pentacoordinated Ir(I) complexes of general formula [(η4-COD)Ir(1-2,5-η-CH2CHCHCHSO2)L] (L = PMe3, 14; PMe2Ph, 15; PMePh2, 16; PPh3, 17; DMSO, 18; and CO, 19) can be obtained, under mild conditions, from 11 and the corresponding ligand L, which shows different σ or π donor–acceptor properties. The disubstituted phosphine derivative
[(η的复分解反应4 -COD)IR(μ-Cl)的] 2(4)与所述thiapentadienide钠两个当量(1NA)或氢sulfinylpentadienide盐(2K)导致相应的二聚体的形成[(η 4 -COD)IR(μ 2 -1-2,5-η-CH 2 CHCHCHS)] 2(5)和[(η 4 -COD铱μ()2 -1-2,5-η-CH 2 CHCHCHSO ]] 2(9)。5和9的单晶分析揭示了通过硫原子和两个铱中心的末端双键桥接的噻戊二烯基或亚磺酰基戊二烯基配体的存在。的治疗5与PME两个当量3产生[(η 4 -COD)IR(1-2.5-η-CH 2 CHCHCHS)PME 3 ](6),而化合物的Ir(1-2.5-η- CH 2 CHCHCHS)(CO)(PPh 3)2(8)由Ir(CO)(Cl)(PPh 3)2(7)与噻戊二烯化钾(1K)反应制得。的1 H和13C NMR支持优选ù构象,并且在同一η