The reactions of cobalt(II) tetrasulphophthalocyanine, [CoII(tspc)]4– with ˙CH3, ˙CH2CH2OH, ˙CH(CH3)CH2OH, ˙CH(CH3)CH(CH3)OH and ˙CH2C(CH3)2OH free radicals have been studied. The results indicate that the first product formed in these reactions has the form [CoII—(tspc—R)]4–, where R is the aliphatic free radical, the exact nature of the bonding of ˙R to tspc is not clear. The complex [CoII—(tspc—R)]4–
钴的反应(II)tetrasulphophthalocyanine,[CO II(T
SPC)] -4-用CH 3,CH 2 CH 2 OH,CH(CH 3)CH 2 OH,CH(CH 3)CH(CH 3)OH和CH 2 C(CH 3)2 OH自由基进行了研究。结果表明,在这些反应中形成的第一产物的形式为[Co II-(t
SPc-R)] 4–,其中R为脂肪族自由基,˙R与t
SPc结合的确切性质尚不清楚。复数[Co II-(t
SPc-R)] 4–在遵循一阶速率定律的过程中重新排列为[(t
SPc)Co III –R] 4–。[(t
SPc)Co III -CH 3 ] 4-分解为[Co III(t
SPc)] 3- + CH 4,而配合物[(t
SPc)Co III -CR 1 R 2 CR 3 R 4 OH] 4-分解进入[Co III(t
SPc)] 3– + R 1 R 2 C CR 3 R 4 +