摘要:
2 当量的反应。吡咯与[C 4 H 3 N(CH 2 NMe 2 )-2] 2 M(NEt 2 ) 2 在甲苯中生成四吡咯金属化合物[C 4 H 3 N(CH 2 NMe 2 )-2] 2 M( C 4 H 4 N) 2 (3, M = Zr; 4, M = Hf) 中等产率。类似地,用庚烷中的 2,6-二甲基苯酚或 2,6-二异丙基苯酚处理金属酰胺 [C 4 H 3 N(CH 2 NMe 2 )-2] 2 M(NEt 2 ) 2 导致消除二乙胺以及形成相应的金属醇盐 [C4H3N(CH2NMe2)-2]2M(OR)2 (5, M = Zr, R = C 6 H 3 -2,6-Me 2 ; 6, M = Hf, R = C 6 H 3 -2,6-Me 2 ; 7, M = Zr, R = C 6 H 3 -2,6-iPr 2 ; 8, M = Hf, R = C 6 H 3 -2,6-iPr