Cocrystallization of baicalein with nicotinamide yields a 1:1 cocrystal [systematic name: pyridine-3-carboxamide–5,6,7-trihydroxy-2-phenyl-4H-chromen-4-one (1/1)], C6H6N2O·C15H10O5. The asymmetric unit contains one baicalein and one nicotinamide molecule, both in neutral forms. Molecules in the cocrystal form column motifs stabilized by an array of intermolecular hydrogen bonds.
黄芩素与烟酰胺的共晶体化产生了 1:1 的共晶体[系统名称:吡啶-3-甲酰胺-5,6,7-三羟基-2-苯基-4H-色烯-4-酮 (1/1)],C6H6N2O-C15H10O5。不对称单元包含一个黄芩素分子和一个烟酰胺分子,两者均为中性形式。共晶体中的分子通过分子间氢键阵列形成柱状结构。