作者:Hans-Friedrich Klein、Andreas Schmidt、Ulrich Flörke、Hans-Jürgen Haupt
DOI:10.1016/s0020-1693(02)01144-1
日期:2003.1
6 H 3 R 4 R 6 (NO 2 )OH] react with Co(PMe 3 ) 4 to afford 2-nitrosophenolatocobalt (I) compounds Co[η 2 - N , O ][C 6 H 2 R 4 R 6 (NO)O](PMe 3 ) 3 ( 1 : R 4 =R 6 =H; 2 : R 4 =Me, R 6 =CMe 3 ). In the molecular structure of 2 the cobalt atom is centered in a trigonalbipyramid of axial O , P and equatorial N , P 2 donor atoms, whereas an isosteric molecule Ni[η 2 - C , O ][C 6 H 2 R 4 R 6 (CO)O](PMe
2-硝基苯酚[C 6 H 3 R 4 R 6(NO 2)OH]与Co(PMe 3)4反应得到2-亚硝基苯酚钴(I)化合物Co [η2-N,O] [C 6 H 2 R 4 R 6(NO)O](PMe 3)3(1:R 4 = R 6 = H; 2:R 4 = Me,R 6 = CMe 3)。在2的分子结构中,钴原子位于轴向O,P和赤道N,P 2供体原子的三角双锥体中,而等排分子Ni [η2-C,O] [C 6 H 2 R 4 R 6含有轴向C,P和赤道O,P 2供体原子的(CO)O](PMe 3)3(2C:R 4 = Me,R 6 = CMe 3)在不同的空间群中结晶。由2-硝基萘酚-1或2-硝基sonaphthol-1与Co(PMe 3)4形成亚硝基钴(I)络合物Co [η2-N,O] [C 10 H 6(NO)O](PMe 3)3( 3)。2-Nitronaphthol-1与过量的Co(PMe