The bifluoride complex,
trans-[Ru(dmpe)
2
(H)(HF
2
)] (dmpe =
Me
2
PCH
2
CH
2
PMe
2
), is generated
by reaction of cis-[Ru(dmpe)
2
H
2
] either
with fluoroarenes (C
6
F
6
, C
6
F
5
H
and others) or by reaction with Et
3
N·3HF; its
solid-state structure, established crystallographically, reveals a
Ru(η
1
-FHF) moiety with a long RuâF bond and an
F···F distance close to that in bifluoride salts,
while the presence of the same complex in solution is shown by
low-temperature NMR spectra.
双
氟络合物,即反式[Ru(dmpe)2(H)(HF2)](dmpe=Me2PCH2CH2PMe2)由顺式[Ru(dmpe)2H2]与
氟芳烃(
C6F6、C6F5H等)或乙基3N·3HF反应生成;其固态结构通过晶体学确定,显示Ru(Ⅲ·1-FHF)部分具有长Ru-F键,且F···F距离接近双
氟盐中的距离;溶液中存在相同络合物可通过低温核磁共振光谱显示。