Reduction of (PPh3)2PtCl2 with hydrazine hydrate in ethanol followed by treatment with an equivalent of an alkyne gave (butynediol)bis(triphenylphosphine)platinum(0), (PPh3)2Pt[C2(CH2OH)2] (I). According to X-ray diffraction data, the Pt atom in complex I has a square environment (Pt-C, 2.036(3) and 2.050(3) Å; Pt-P, 2.2719(8) and 2.2817(7) Å). In the coordinated butynediol, the C=C bond is lengthened(1
在
乙醇中用
水合
肼还原(PPh 3)2 PtCl 2,然后用等价的
炔烃处理,得到(
丁炔二醇)双(
三苯基膦)
铂(0),(PPh 3)2 Pt [C 2(CH 2 OH)2 ](I)。根据X射线衍射数据,配合物I中的Pt原子具有正方形环境(Pt-C,2.036(3)和2.050(3); Pt-P,2.2719(8)和2.2817(7))。在配位的
丁炔二醇中,C = C键加长(1.287(4)Å),角度CC≡C减小至140.3(3)°和144.6(3)°,这可能是由于四个电子的贡献
铂原子。在
水晶中,复杂的我 形成通过相邻分子的羟基之间的氢键稳定的二聚体。