The reaction of iodomethane and acetylene in the presence of PtII and NaI in acetone gives (E)-1-iodopropene. A possible mechanism involves the intermediate formation of a PtIV methyl vinyl derivative by the iodoplatination of acetylene with a reversibly formed a PtIV methyl complex and assumes the catalytic character of the process.
在
丙酮中,
碘甲烷和
乙炔在 PtII 和 NaI 的存在下发生反应,生成 (E)-1-
碘丙烯。一种可能的机理是,
乙炔与可逆形成的 PtIV 甲基复合物发生
碘化反应,中间形成 PtIV 甲基
乙烯基衍
生物,并假定该过程具有催化特性。