dichloro(1,5,9,13-tetrathiacyclohexadecane)rhodium(III) chloride | 135694-47-2

• 分子结构分类: 有机化合物 - 有机杂环化合物
• 英文名称: dichloro(1,5,9,13-tetrathiacyclohexadecane)rhodium(III) chloride
• 英文别名: 1,5,9,13-Tetrathiacyclohexadecane;trichlororhodium；1,5,9,13-tetrathiacyclohexadecane;trichlororhodium
• CAS: 135694-47-2
• 化学式: C₁₂H₂₄Cl₂RhS₄*Cl
• 分子量: 505.851
• InChiKey: GLMRUWSRQLMYQR-UHFFFAOYSA-K

计算性质

• 辛醇/水分配系数(LogP)：
  6.56
• 重原子数：
  20
• 可旋转键数：
  0
• 环数：
  1.0
• sp3杂化的碳原子比例：
  1.0
• 拓扑面积：
  101
• 氢给体数：
  0
• 氢受体数：
  4

反应信息

• 作为产物：
  描述：

  1,5,9,13-四硫杂环十六烷 、 无水氯化铑(III) 以 乙醇 、 二氯甲烷 为溶剂， 以34%的产率得到dichloro(1,5,9,13-tetrathiacyclohexadecane)rhodium(III) chloride
  参考文献：
  名称：

  Cobalt(II) and rhodium(III) complexes of 1,5-dithiacyclooctane (1,5-DTCO) and 1,5,9,13-tetrathiacyclohexadecane (TTH)

  摘要：

  Complexes of 1,5-dithiacyclooctane (1,5-DTCO) and 1,5,9,13-tetrathiacyclohexadecane (TTH) with cobalt(II) and rhodium(III) are reported. Co(BF4)2 reacts with either 1,5-DTCO or TTH to form square pyramidal complexes [Co(1,5-DTCO)2CH3CN]2+ and [Co(TTH)CH3CN]2+. The CH3CN cannot be removed from the 1,5-DTCO complex. CoCl2 reacts with TTH to form tetrahedral [Co(TTH)]2+ and [CoCl4]2- ions. CoCl2 reacts with 1,5-DTCO to form a solid with an empirical formula of Co(1,5-DTCO)2Cl2, which, when dissolved in nitromethane, dissociates to form tetrahedral [Co(1,5-DTCO)Cl2]. RhCl3 reacts with 1,5-DTCO and TTH to form trans-octahedral complexes of the form, trans-[RhS4Cl2]+.

  DOI：

  10.1016/s0020-1693(00)85181-6

文献信息

• Cobalt(II) and rhodium(III) complexes of 1,5-dithiacyclooctane (1,5-DTCO) and 1,5,9,13-tetrathiacyclohexadecane (TTH)
  作者：Thomas L. Wolford、W.Kenneth Musker

  DOI：10.1016/s0020-1693(00)85181-6

  日期：1991.4

  Complexes of 1,5-dithiacyclooctane (1,5-DTCO) and 1,5,9,13-tetrathiacyclohexadecane (TTH) with cobalt(II) and rhodium(III) are reported. Co(BF4)2 reacts with either 1,5-DTCO or TTH to form square pyramidal complexes [Co(1,5-DTCO)2CH3CN]2+ and [Co(TTH)CH3CN]2+. The CH3CN cannot be removed from the 1,5-DTCO complex. CoCl2 reacts with TTH to form tetrahedral [Co(TTH)]2+ and [CoCl4]2- ions. CoCl2 reacts with 1,5-DTCO to form a solid with an empirical formula of Co(1,5-DTCO)2Cl2, which, when dissolved in nitromethane, dissociates to form tetrahedral [Co(1,5-DTCO)Cl2]. RhCl3 reacts with 1,5-DTCO and TTH to form trans-octahedral complexes of the form, trans-[RhS4Cl2]+.