Transamidation reactions. Part 11.N-substituted 3-aminopropanenitriles and 2-aminoacetonitriles asSchiff-base equivalents
作者:Elefteria Askito??lu、Armin Guggisberg、Manfred Hesse
DOI:10.1002/hlca.19850680325
日期:1985.5.15
a strong base, the 13-membered cyclic compound 3 yielded, by loss of acetonitrile or its equivalent, the bicyclic product 5 instead of the 17-membered compound 4 as expected (Scheme 2). Investigation of model compounds (Scheme 4) and of model reactions (Schemes 5 and 6) led to the conclusion that the reaction proceeds via an intermediate formaldehyde imine; a Schiff base, e.g.3b(Scheme 5), which reacts
在强碱的存在下,由于乙腈或其等同物的损失,该13元环状化合物3产生了双环产物5而不是预期的17元化合物4 (方案2)。对模型化合物(方案4)和模型反应(方案5和6)的研究得出的结论是,反应是通过中间体甲醛亚胺进行的。一席夫碱,例如3B (方案5) ,该反应区域内和分子间用亲核试剂,以形成曼尼希型产品。似乎普遍的原则是,N-取代的3-氨基丙腈和2-氨基乙腈衍生物在强碱的存在下表现为席夫碱等价物(方案5和6)。