Syntheses of the Antimonides R2Sb? (R = Ph, Mes,tBu,tBu2Sb) and Sb73? by Reactions of Organoantimony Hydrides orcyclo-(tBuSb)4 with Li, Na, K, or BuLi
作者:H. J. Breunig、M. E. Ghesner、E. Lork
DOI:10.1002/zaac.200400497
日期:2005.4
Reactions of R2SbH with BuLi at −70 °C in tetrahydrofuran (thf) lead to [R2SbLi(thf)3] [R = Ph (1) or R = Mes (2)]. The antimonides [tBu2SbK(pmdeta)] (3) (pmdeta = pentamethyldiethylenetriamine), [Li(tmeda)2][tBu4Sb3]·benzene (4) (tmeda = tetramethylethylenediamine), and [tBu4Sb3Na(tmeda, thf)] (5) result from the reduction of cyclo-(tBuSb)4 by Li, Na, or K with pmdeta or tmeda in thf. The primary
R2SbH 与 BuLi 在 -70 °C 下在四氢呋喃 (thf) 中反应生成 [R2SbLi(thf)3] [R = Ph (1) 或 R = Mes (2)]。锑化物 [tBu2SbK(pmdeta)] (3) (pmdeta = 五甲基二亚乙基三胺)、[Li(tmeda)2][tBu4Sb3]·苯 (4) (tmeda = 四甲基乙二胺) 和 [tBu4Sb3Na(tmeda, thf)] (5)由 Li、Na 或 K 在 thf 中用 pmdeta 或 tmeda 还原 cyclo-(tBuSb)4 产生的。RSbH2 [R = Mes (6), 2-(Me2NCH2)C6H2 (7)] 由 RSbCl2 与 LiAlH4 反应合成。PhSbH2 与 BuLi 和 tmeda 在甲苯中反应生成 [Sb7Li3(tmeda)3]·甲苯 (8)。[Sb7Na3(pmdeta)3]·甲