them from chemical syntheses. Cyclic voltammograms for [RhL2Cl4]–(L = PEt3, SMe2, SeMe2, or py) show that oxidation occurs at more positive potentials, but the rhodium(IV) complexes are unstable. Neutral iridium(III) complexes [IrL3X3] are not oxidised by X2 or HNO3, and possible reasons for this and the crucial role of the [IrL2X4]– intermediates in the preparation of [IrL2X4] are discussed.
铱(III)阴离子的反式- [IRL 2
氯4 ] - [L =
吡啶(PY),PET 3,PET 2 PH,PEtPh 2,A
SET 3,ASME 2 PH,SMe的2,或
SEME 2 ]已制备并用
氯氧化为紫色
铱(IV)反式-[IrL 2 Cl 4 ]。深绿色反式-[IrL 2 Br 4 ](L = py ,PEt 3,PMe 2 Ph,A
SEt 3,AsMe 2从反式-[IrL 2 Br 4 ] -和Br 2或HNO 3相似地获得Ph或SMe 2)。[IrL 2 Cl 4 ](L = PPh 3 AsPh 3或SbPh 3)直接由IrCl 3 · n H 2 O + 2L制备,然后
氯化生成的中间体[(IrL 2 Cl 3)n ];顺式-[IrL 2 Cl 4 ](L = py或SbMe 3)和还描述了反式-[IrL 2 X 4 ] –(L = TeMe 2,X = Cl; L =
SEMe