Separation of (S)-(−)-3-Methyl-2-pyrrolidinone as an Inclusion Complex with (R)-(+)-4,4′,6,6′-Tetrachloro-2,2′-bis(hydroxydiphenylmethyl)-1,1′-biphenyl Host and its X-ray Structural Study
作者:Tanya le Roex、Luigi R. Nassimbeni、Fumio Toda
DOI:10.1007/s10870-007-9312-8
日期:2008.1
By inclusion complexation with the chiral host compound (R)-(+)-4,4′,6,6′-tetrachloro-2,2′-bis(hydroxydiphenylmethyl)-1,1′-biphenyl, racemic 3-methyl-2-pyrrolidinone was resolved and its (S)-(−)-enantiomer was isolated as a 1:1 inclusion complex, which crystallises in the orthorhombic crystal system in the space group P212121 (a = 14.1163(2) Å, b = 14.7140(3) Å, c = 17.2025(3) Å). By the inclusion complexation, the keto–enol equilibrium of the guest was frozen and the keto-form was isolated in a pure form. By X-ray structural study of the complex, the guest molecule included was elucidated to be the keto-form and its absolute configuration was determined to be (S). By inclusion complexation with (R)-(+)-4,4′,6,6′-tetrachloro-2,2′-bis (hydroxydiphenylmethyl)-biphenyl, racemic 3-methyl-2-pyrrolidinone was resolved and its (S)-(−)-enantiomer isolated and in addition the keto–enol equilibrium of the guest was frozen and the keto-form isolated.
通过与手性主体化合物(R)-(+)-4,4',6,6'-四氯-2,2'-双(羟基二苯基甲基)-1,1'-联苯的包合络合,得到外消旋3-甲基- 2-吡咯烷酮被解析,其 (S)-(−)-对映体被分离为 1:1 包合物,在空间群 P212121 的斜方晶系中结晶 (a = 14.1163(2) Å,b = 14.7140 (3) Å, c = 17.2025(3) Å)。通过包合络合,客体的酮-烯醇平衡被冻结,并且酮形式以纯形式分离。通过对该配合物的X射线结构研究,确定所包含的客体分子为酮型,其绝对构型确定为(S)。通过与(R)-(+)-4,4',6,6'-四氯-2,2'-双(羟基二苯基甲基)-联苯的包合络合,拆分出外消旋3-甲基-2-吡咯烷酮,并得到其(S )-(−)-对映异构体被分离,此外客体的酮-烯醇平衡被冻结并分离出酮形式。