Schiff-base complexes of the lanthanoids and actinoids. Part 1. Lanthanoid(<scp>III</scp>) halide complexes with the un-ionised form of NN′-ethyl-enebis(salicylideneimine) and related bases
作者:Joseph I. Bullock、Heidar-Ali Tajmir-Riahi
DOI:10.1039/dt9780000036
日期:——
base NN′-ethylenebis(salicylideneimine) and related bases, H2L, react with hydrated lanthanoid(III) halides to give the complexes Ln(H2L)Cl3·nH2O (Ln = La or Ce; n= O—2), Ln2(H2L)3Cl6·nH2O (Ln = La, Ce, Pr, Nd, Sm, Gd, Ho, or Yb; n= O–2). Ln(H2L)2X3·nH2O (Ln = La, Ce, Pr, Nd, Sm, Gd, Ho, or Yb; X = Cl or Br; n= O–2). and Ln(H2L)3X3·nH2O (Ln = La, Ce, Pr, Nd, Sm. or Gd; X = Cl or Br; n= 0 or 1). Spectroscopic
席夫碱NN '-ethylenebis(salicylideneimine)和相关的碱,H 2 L,与水合镧系(反应III)卤化物,得到复合物LN(H 2 L)氯3 · Ñ ħ 2 O(LN =的La或Ce; n = O-2),Ln 2(H 2 L)3 Cl 6 · n H 2 O(Ln = La,Ce,Pr,Nd,Sm,Gd,Ho或Yb;n = O-2)。Ln(H 2 L)2 X 3 · n H 2 O(Ln = La,Ce,Pr,Nd,Sm,Gd,Ho或Yb; X = Cl或Br;n = O–2)。Ln(H 2 L)3 X 3 · n H 2 O(Ln = La,Ce,Pr,Nd,Sm。或Gd; X = Cl或Br;n= 0或1)。光谱学和其他证据表明:(i)卤化物与金属离子配位,但Ln(H 2 L)3 X 3 · n H 2 O的结果不明确时除外;(ii)潜在的四元配体在这些配合物中是双齿的,未电离的酚基是不配位的。