The condensation of a methyl group at the 6- of 8-position on the 9H-purine ring with benzaldehyde and ethyl benzoate in the presence of sodium hydride occurred to give the styryl- (4a, b) and phenacyl-9H-purines (5a, b and 6a, b). Conversion of the metyl group into a formyl group was achieved by treatment with selenium dioxide in dioxane, giving the 9H-purinecarboxaldehydes (7a, b and 8a, b).
在氢化
钠存在下,9H-
嘌呤环上8位和6位的甲基团与
苯甲醛和乙苯酸酯发生缩合反应,得到斯蒂尔基-(4a,b)和
苯乙酰基-9H-
嘌呤(5a,b和6a,b)。将甲基转化为甲酰基是通过在
二噁烷中用
二氧化硒处理实现的,得到9H-
嘌呤羧醛(7a,b和8a,b)。