从溶液中合成新的结晶Pu(V)化合物:III。 n = 3、1和0的NaPuO 2 C 2 O 4 · n H 2 O的 合成与研究
摘要:
NaPuO 2 c ^ 2 Ò 4 ·3H 2 O的从浦(VI)的还原与水合肼的化学计量量的新鲜制备的草酸溶液中分离。化合物的加热导致其逐步脱水,并依次形成一水合物和无水盐。根据粉末X射线图,NaPuO 2 C 2 O 4 · n H 2 O( n = 3,4)与相应的类似物NaNpO 2 C 2 O 4 · n H 2 O同构。NaNpO的晶胞参数2确定了C 2 O 4 ·H 2 O和NaPuO 2 C 2 O 4 · n H 2 O( n = 3,1)。X射线分析的结果以及庚基(V)和p基(V)结晶化合物的电子和IR光谱表明,NaPuO 2 C 2 O 4 · n H 2 O( n = 1,0)。
作者:N. N. Krot、A. A. Bessonov、I. A. Charushnikova、V. I. Makarenkov
DOI:10.1134/s1066362207020014
日期:2007.4
Neptunium(V) at its relatively high concentrations in oxalate solutions forms, along with the mono-and bioxalate complexes, the intermediate binuclear anion (NpO2)(2)(C2O4)(3)(4-). This anion gradually crystallizes from cold aqueous-ethanol solutions in the form of the compound Na-4(NpO2)(2)(C2O4)(3) center dot 6H(2)O, and from hot aqueous-ethanol solutions, in the form of a lower hydrate, Na-4(NpO2)(2)(C2O4)(3) center dot 2H(2)O. Both compounds were characterized by powder X-ray diffraction and by electronic absorption and IR spectra. The thermal behavior of the hexahydrate in air was studied. Attempts to prepare the related crystalline compounds M-4(NpO2)(2)(C2O4)(3) center dot nH(2)O with M = Li or NH4 failed.