This invention relates to the preparation of 13-oxabicyclo[10.3.0]pentadecane. More specifically, this invention relates to a process for preparing 13-oxabicyclo[10.3.0]pentadecane which comprises the steps of: (a) reacting cyclododecanone with elemental bromine in an organic solvent to form .alpha.-bromocyclododecanone; (b) reacting .alpha.-bromocyclododecanone with malonic acid dialkyl ester and alkali metal alcoholate to form the ketodiester 2-(2-oxocyclododec-1-yl)-malonic acid dialkyl ester; (c) hydrolyzing and decarboxylating the ketodiester from step (b) to from the corresponding 2-oxocyclododec-1-yl-acetic acid in an aqueous alkaline solution; (d) purifying the product of step (c) by extraction with an organic solvent and obtaining 2-oxocyclododec-1-yl-acetic acid; (e) reacting the product of step (d) with a lower alcohol to form a corresponding ester; (f) reducing the product of step (e) with a complex metallic hydride to form 2-(2-hydroxyethyl)-cyclododecanol; and (g) heating the product of step (f) in the presence of an acid catalyst to form 13-oxabicyclo[10.3.0]pentadecane.
本发明涉及制备13-氧代双环[10.3.0]
十五烷的方法。具体而言,本发明涉及一种制备13-氧代双环[10.3.0]
十五烷的方法,包括以下步骤:(a)在有机溶剂中反应
环十二酮和
溴元素以形成α-
溴代
环十二酮;(b)将α-
溴代
环十二酮与
马来酸二烷基酯和碱
金属醇盐反应以形成酮二酯2-(2-氧代
环十二烷-1-基)-
马来酸二烷基酯;(c)在碱性
水溶液中
水解和脱羧来自步骤(b)的酮二酯以形成相应的2-氧代
环十二烷-1-基
乙酸;(d)通过有机溶剂萃取纯化步骤(c)的产物并获得2-氧代
环十二烷-1-基
乙酸;(e)将步骤(d)的产物与低级醇反应以形成相应的酯;(f)用复合
金属
氢化物还原步骤(e)的产物以形成2-(2-羟乙基)-
环十二醇;(g)在酸催化剂存在下加热步骤(f)的产物以形成13-氧代双环[10.3.0]
十五烷。