Synthesis of Re-Ru heterobimetallic polyhydride complexes. Study of the influence of ligands bonded to the monometallic precursors on the nature of the isolated binuclear complexes
摘要:
The reaction of K[H(6)ReL(2)] with [RuHCl(CO)(PPh(3))(3-x){P(OPri}3)(x)](L(2) = (PMePh(2))(2), dppe,(AsPh(3))(2), or (PPh(3))(2); x = 0, 1 or 2) leads to [L(2)(CO)HRe(mu-H)(3)RuH(PPh(3))(2-y){P(OPri)(3)}(y)](x = 0 or 1, y = 0; x = 2, y = 1(L(2) = PPh(3))) in a first step. Under the reaction conditions most of these complexes react rapidly with the liberated phosphine giving [L(2)(CO)Re(mu-H)(3)Ru(PPh(3))(3-y)-{P(OPri)(3))(y)] (L(2) = (PMePh(2))(2) or dppe, y = 0; L(2) = (PPh(3))(2) y = 1) as the only isolable complexes. The structure of [(PMePh(2))(2)(Co)Re(mu-H)(3)Ru(PPh(3))(3)] has been established by X-ray structure analysis. The complex [(PPh(3))(2)(CO)Re(mu-H)(3)Ru(PPh(3))(2)(P(OPri)(3))] reacts with molecular hydrogen under pressure to generate [L(2)(CO)HRe(mu-H)(3)RuH)PPh(3))(P(OPri)(3)) as the sole product.
The synthesis of ReH7(AsPh(3))(2) is reported. Surprisingly, this complex appears to be a classical heptahydride and is remarkably resistant to substitution by nitrogen and phosphorus donor ligands. The reactivity of this polyhydride towards silanes and stannanes was also studied. The new complexes, ReH6(SiPh(3))(AsPh(3))(2) and ReH6(SnPh(3))(AsPh(3))(2), are formed with Ph(3)EH (E = Si,Sn) but ReH7(AsPh(3))(2) does not react with chelating silanes. These products appear to be more stable than their phosphine-supported analogues.