作者:J. M. Vierfond、A. Reynet、H. Moskowitz、C. Thal
DOI:10.1080/00397919208020498
日期:1992.6
Pummerer's ketone 1 is obtained with an overall yield of 55 % by the following sequence: Claisen rearrangement of an arylcyclohexylether 3; allylic oxidation of the methylcycloalkylphenolic derivative 4b, then spontaneous cyclisation during demethylation to give 2. 1 is obtained by dehydrogenation of 2. NMR data agree with a cis stereochemistry at C4a and C 9b.
摘要 Pummerer 酮 1 以 55% 的总收率通过以下顺序获得:芳基环己醚 3 的克莱森重排;甲基环烷基酚衍生物4b的烯丙基氧化,然后在去甲基化过程中自发环化得到2。1通过2的脱氢获得。NMR数据与C4a和C9b的顺式立体化学一致。