Organometallic chemistry of diphosphazanes—13.1 Palladium complexes of unsymmetrical diphosphazanes Ph2PN(Pri)PYY′
作者:Ruppa P. Kamalesh Babu、Setharampattu S. Krishnamurthy、Munirathinam Nethaji
DOI:10.1016/0277-5387(95)00561-7
日期:1996.8
Unsymmetrical diphosphazanes Ph2PN(Pri)PYY′ [] react with cis-[PdCl2(COD)] (COD = cycloocta-1,5-diene) giving the chelate complexes of the type cis-[PdCl2η2-Ph2PN(Pri)PYY′}] []. The PN bond in 3 and 5 undergoes a facile cleavage in methanol solution to give cis-[PdCl2η1-Ph2P(OMe)}η1-PhP(NHPri)(Y′)}] [Y′ = OC6H4Br-4 (7), OC6H3Me2-3,5 (8)]. Reactions of Pd2(dba)·CHCl3 (dba = dibenzylideneacetone)
不对称diphosphazanes博士2 PN(镨我)PYY'[ ]与反应顺式- [的PdCl 2(COD)](COD =环辛-1,5-二烯),给出的类型的螯合配合物的顺式- [的PdCl 2 η 2 -Ph 2 PN(Pr i)PYY'}] [ ]。在PN键3分5经受一个浅显的裂解在甲醇溶液中,得到顺式- [的PdCl 2 η 1 -Ph 2 P(OME)} η 1 -PHP(NHPr我)(Y')}] [ Y'= OC 6H 4 Br-4(7),OC 6 H 3 Me 2 -3,5(8)]。钯的反应2(DBA)·氯仿3(DBA =苄基丙酮)与diphosphazanes博士2 PN(镨我)PPhY'[Y'= OC 6 H ^ 4 ME-4(大号4),N 2 ç 3 HME 2 -在MeI存在下3,5,(L 6),N 2 C 3 H 3(L 7)产生顺式-[PdI 2 η 2