Dimeric and monomeric palladium(II) parent-amido (NH2) complexes: Synthesis, characterization, and reactivity
作者:Youngwon Kim、Soonheum Park
DOI:10.1016/j.crci.2015.05.007
日期:2015.8
Résumé The treatment of [PdL3(NH3)]OTf (L3 = (PEt3)2(Ph) (1), (2,6-(Cy2PCH2)2C6H3) (3)) with NaNH2 in THF afforded dimeric and monomeric parent-amido palladium(II) complexes with bridging and terminal NH2, respectively, anti-[Pd(PEt3)(Ph)(μ-NH2)]2 (2) and Pd(2,6-(Cy2PCH2)2C6H3)(NH2) (4). The dimeric complex 2 crystallizes in the space group P21/n with a = 13.228(2) Å, b = 18.132(2) Å, c = 24.745(2) Å, β = 101.41(1)°, and Z = 4. It has been found that there are two crystallographically independent molecules with Pd(1)–Pd(2) and Pd(3)–Pd(4) distances of 2.9594 (10) and 2.9401(9) Å, respectively. The monomeric amido complex 4 protonates from trace amounts of water to give the cationic ammine species [Pd(2,6-(Cy2PCH2)2C6H3)(NH3)]+. Complex 4 reacts with diphenyliodonium triflate ([Ph2I]OTf) to give aniline complex [Pd(2,6-(Cy2PCH2)2C6H3)(NH2Ph)]OTf (5). Reaction of 4 with dialkyl acetylenedicarboxylate (DMAD, DEAD) yields diastereospecific palladium(II) vinyl derivative (Z)–(Pd(Cy2PCH2)2C6H3)(CR = CR(NH2)) (R = CO2Me (6a), CO2Et (6b)). Reacting complexes 6a and 6b with p-nitrophenol produces (Pd(Cy2PCH2)2C6H3)(OC6H4–p-NO2) (8) and cis-CHR = CR(NH2), exclusively. Supplementary Materials: Supplementary material for this article is supplied as a separate file: mmc1.docx
在 THF 中用 NaNH2 处理 [PdL3(NH3)]OTf (L3 = (PEt3)2(Ph) (1), (2,6-(Cy2PCH2)2C6H3) (3)) 得到二聚体和单体母体酰胺基分别与桥接和末端 NH2 形成的钯 (II) 配合物,抗 [Pd(PEt3)(Ph)(μ-NH2)]2 (2) 和 Pd(2,6-(Cy2PCH2)2C6H3)(NH2) (4 )。二聚配合物2在空间群P21/n中结晶,a = 13.228(2) Å,b = 18.132(2) Å,c = 24.745(2) Å,β = 101.41(1)°,Z = 4。研究发现,存在两种晶体学上独立的分子,其 Pd(1)-Pd(2) 和 Pd(3)-Pd(4) 距离分别为 2.9594 (10) 和 2.9401(9) Å。单体酰胺络合物 4 从痕量水中质子化,得到阳离子氨胺物质 [Pd(2,6-(Cy2PCH2)2C6H3)(NH3)]+。络合物 4 与三氟甲磺酸二苯基碘 ([Ph2I]OTf) 反应,得到苯胺络合物 [Pd(2,6-(Cy2PCH2)2C6H3)(NH2Ph)]OTf (5)。 4 与乙炔二甲酸二烷基酯 (DMAD, DEAD) 反应生成非对映特异性钯 (II) 乙烯基衍生物 (Z)–(Pd(Cy2PCH2)2C6H3)(CR = CR(NH2)) (R = CO2Me (6a), CO2Et (6b) )。配合物 6a 和 6b 与对硝基苯酚反应仅生成 (Pd(Cy2PCH2)2C6H3)(OC6H4–p-NO2) (8) 和 cis-CHR = CR(NH2)。 补充材料:本文的补充材料作为单独的文件提供:mmc1.docx