The dihydride Ru(C6Me6)[PH(C6H11)2]H2 is synthesized in high yield by reducing Ru(C6Me6)[PH(C6H11)2]Cl2 with Na[AlH2(OCH2CH2OMe)2]. In benzene it loses hydrogen under UV irradiation to give Ru(C6Me6)[PH(C6H11(2]H(C6H5).
通过用Na [ ]还原Ru(C 6 Me 6)[PH(C 6 H 11)2 ] Cl 2可以高产率合成二
氢化物Ru(C 6 Me 6)[PH(C 6 H 11)2 ] H 2。 AlH 2(OCH 2 CH 2 OMe)2 ]。在苯中,它在紫外线照射下会损失氢原子,从而得到Ru(C 6 Me 6)[PH(C 6 H 11(2 ] H(C 6 H 5))。