作者:H. Werner、J. Wolf、U. Schubert、K. Ackermann
DOI:10.1016/0022-328x(86)80543-5
日期:1986.12
on treatment of XI with hydride donors such as Li[BEt3H] or Red-al the cis-stilbene complex C5H5Rh(Z-CHPhCHPh)PPri3 (XVII) is formed. The reaction of C5H5Rh(PhC2H)PPri3 (VI) with CF3CO2H gives the compound C5H5Rh(CPhCH2)(PPri3)OCOCF3 (XXIV) which reacts with NaI to give the corresponding iodo derivative C5H5Rh(CPhCH2)(PPri3)I (XXV). Using deuterium-labeling experiments, the mechanism of formation
方形化合物反式-[RhCl(RC 2 R')(PPr i 3)2 ](II:RR'H; III:RH,R'Ph; IV:RR' Ph)由[(C 8 H 14)2 RhCl] 2,PPr i 3和炔烃经中间体[RhCl(PPr i 3)2 ]制备。III和IV与NaC 5 H 5的反应产生相应的环戊二烯基络合物C 5 H 5 Rh(RC 2 R')-PPr i 3(V,VI)。同样地,以[(C 8 H 14)2 RhCl] 2为起始原料,得到化合物C 5 H 5 Rh(C 2 Ph 2)PMe 3(IX)。C 5 H 5 Rh(C 2 Ph 2)PPr i 3(V)与CF 3 CO 2 H的反应导致形成乙烯基络合物C 5 H 5 Rh(E- CPhCHPh)(PPr i 3 OCOCF 3在布朗斯台德酸的存在下,作为甲醇的式(XI)反应,得到金属镧系元素衍生物C 5 H 5(PPr