[(AuPPh3)3(μ-(CC)3C6Me3-2,4,6)] | 871209-34-6

• 分子结构分类: 有机化合物 - 苯类化合物 - 苯和取代衍生物
• 英文名称: [(AuPPh3)3(μ-(CC)3C6Me3-2,4,6)]
• CAS: 871209-34-6
• 化学式: C₆₉H₅₄Au₃P₃
• 分子量: 1567.01
• InChiKey: OKJVLSXUYPJUMP-UHFFFAOYSA-N

计算性质

• 辛醇/水分配系数(LogP)：
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• 重原子数：
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• 可旋转键数：
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• 环数：
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• sp3杂化的碳原子比例：
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• 拓扑面积：
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• 氢给体数：
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• 氢受体数：
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反应信息

• 作为产物：
  描述：

  gold (acetylacetonato) triphenylphosphane 、 1,3,5-triethynylmesitylene 以 二氯甲烷 为溶剂， 以87%的产率得到[(AuPPh3)3(μ-(CC)3C6Me3-2,4,6)]
  参考文献：
  名称：

  Gold(I) Complexes Derived from C₆Me₃(C⋮CH)₃-1,3,5, C₆Me₄(C⋮CH)₂-1,4, and MeC₆H₄C⋮CH-4

  摘要：

  C6Me3(C CH)(3)-1,3,5 (Ar(C CH)(3)) reacts with [AuCl(SMe2)] and NEt3 (1:3:3) to give [Au-3{mu-(C=C)(3)Ar}](n) (1). Complexes of the general formula [{AuL}(3){mu-(C C)(3)Ar}] can be obtained from 1 and excess isocyanide (L = (BuNC)-Bu-t (2), XyNC (3)), by treating 2 with an excess of NHEt2 (L = C((NHBu)-Bu-t)NEt2 (4)), or by reacting [Ar(C CH)(3)] with [Au(acac)PPh3] (1:3, L = PPh3 (5)) or with PPN[AuCl2] (1:3, PPN = Ph3P=N=PPh3) and an excess of NHEt2 (L = NHEt2 (6)). The reaction of C6Me4(C CH)(2)-1,4 (Ar'(C CH)(2)) with PPN[AuCl2] (1:2) and an excess of NHEt2 gives [{AuNHEt2}(2){mu-(C C)(2)Ar'}] (7), which reacts with 1,6-bis(diphenylphosphino)hexane (dpph) to give [Au-2{mu-(C C)(2)Ar'}(mu-dpph)](n) (8). The reactions of the alkynes [Ar(C CH)(3)], [Ar'(C CH)(2)], and ToC CH (To = 4-MeC6H4) with the appropriate amounts of PPN[Au(acaC)(2)] (acac = acetylacetonato) allow the syntheses of the anionic complexes PPN[Au{C CAr(C CH)(2)}2] (9), PPN[Au{C CAr'C=CH}(2)] (10), PPN[Au{C CTo}(2)] (11), (PPN)(3n)[Au{C CAr(C C)2J2AU21, (12), and (PPN),[Aufu-(C=C)2Ar'J1, (13). The X-ray crystal structures of 5, 9, and 11 have been determined.

  DOI：

  10.1021/om050665f