-C 6 H 5 (8)], respectively. The reaction of 5 or 6 with an excess of NaCl(aq.) in acetone affords the orthometallated palladium(II) complexes [PhN=C(CMe 2 )(N-η 1 -Ph)C=N(E)}PdCl] [E = -(CH 2 ) 2 OMe (9); -(CH 2 )C(O)OMe (10)], whereas the reaction of 7 with an excess of NaCl(aq.) in acetone affords the dinuclear palladium(II) complex [[PhN=C(CMe2)(N-η 1 -Ph)C=N(CH 2 ) 2 CH 3 ]-PdCl} 2 ] (11). The
四种
配体前体,即PhN=C(CMe2)(NPh)C=N(E)[E=-(CH 2 ) 2 OMe(1);-(CH 2 )C(O)OMe (2);-(CH 2 ) 2 CH 3 (3);-C 6 H 5 (4)],进行了描述。在THF或CH 3 CN中用1-1.1摩尔当量的Pd(OAc) 2 处理1、2、3或4得到原
金属化
钯(II)配合物[[PhN=C(CMe 2 )-(N-η) 1 -Ph)C=N(E)]Pd(OAc)} 2 ] [E = -(CH 2 ) 2 OMe (5); -(CH 2 )-C(O)OMe (6);-(CH 2 ) 2 CH 3 (7);-C 6 H 5 (8)],分别。5 或 6 与
丙酮中过量的 NaCl(aq.) 反应得到正
金属化
钯 (II) 配合物 [PhN=C(CMe 2 )(N-η 1 -Ph)C=N(E)}PdCl ] [E = -(CH 2 ) 2 OMe