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[RuH(1,5-cod)(PMe2Ph)3](PF6) | 40988-88-3

中文名称
——
中文别名
——
英文名称
[RuH(1,5-cod)(PMe2Ph)3](PF6)
英文别名
[RuH(1,5-cod)(PMe2Ph)3](PF6)
[RuH(1,5-cod)(PMe2Ph)3](PF6)化学式
CAS
40988-88-3
化学式
C40H56O10P5Ru*F6P
mdl
——
分子量
1097.78
InChiKey
JOCLVMDDPSAPKQ-UHFFFAOYSA-N
BEILSTEIN
——
EINECS
——
  • 物化性质
  • 计算性质
  • ADMET
  • 安全信息
  • SDS
  • 制备方法与用途
  • 上下游信息
  • 反应信息
  • 文献信息
  • 表征谱图
  • 同类化合物
  • 相关功能分类
  • 相关结构分类

计算性质

  • 辛醇/水分配系数(LogP):
    12.7
  • 重原子数:
    63.0
  • 可旋转键数:
    20.0
  • 环数:
    5.0
  • sp3杂化的碳原子比例:
    0.25
  • 拓扑面积:
    92.3
  • 氢给体数:
    0.0
  • 氢受体数:
    10.0

反应信息

  • 作为产物:
    描述:
    二甲基苯基膦酸盐fac-[RuH(1,5-cod)(NH2NMe2)3](PF6)甲醇 为溶剂, 以86%的产率得到[RuH(1,5-cod)(PMe2Ph)3](PF6)
    参考文献:
    名称:
    The dominant steric effect in the synthesis of ammine hydrido- and chlorido-Ru(II)- N , N -dimethylhydrazine and mixed alkyl–aryl phosphine complexes: Novel methyldiazene reduction intermediates
    摘要:
    Novel cationic hydrido complexes [RuH(1,5-cod)(NH3)(NH2NMe2)(2)](X) (X = PF6, BPh4) and chloridoammine complexes [RuCl(1,5-cod)(NH3)(2)(NH2NMe2)](X) (X = PF6, BPh4), were isolated from the reaction of the polymeric [RuCl2(1,5-cod)](x) with NH2NMe2. Reaction of the hydrido complexes with the phosphine ligands PMe3, PMe2Ph, P(OMe)(2)Ph resulted in the formation of monohydrido-phosphine complexes, whereas reaction with the bulkier PMePh2 ligand gave dihydrido-phosphine complexes. Similar reactions of the chlorido-ammine complexes with the phosphine ligands PMe3, PMe2Ph, P(OMe)(2)Ph, and PMePh2 all sequentially substituted the NH2NMe2 and the 1,5-cod ligands to give the chlorido-ammine phosphine complexes. All complexes were fully characterised and the single crystal X-ray structures were determined for [RuH{P(OMe)(2)Ph}(5)](BPh4), [RuH2(PMePh2)(4)], [{Ru(PMe2Ph)(3)}(2)(mu-F)(3)](PF6), fac-[RuCl (NH3) (2)(PMe2Ph)(3)](PF6), and [RuCl(NH3)(PMe2Ph)(4)](PF6). Intramolecular strain between coordinated sigma-donor ligands in the Ru(II)-NH2NMe2 precursor complexes as well as the relative steric bulk of incoming r-donor ligands were found to be chemically directing in the formation of monohydrido-, bishydrido, mono-ammine, and bis-ammine ruthenium(II) complexes. (C) 2015 Elsevier B.V. All rights reserved.
    DOI:
    10.1016/j.ica.2015.08.019
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文献信息

  • Cationic ruthenium systems. Part 4. Bridge-splitting reactions of the triply bridged dimers bis(η-cyclo-octa-1,5-diene)(NN-dimethylhydrazine)dihalogenodihydridodiruthenium with a series of neutral donor ligands
    作者:Terence V. Ashworth、Rolf H. Reimann、Eric Singleton
    DOI:10.1039/dt9780001036
    日期:——
    The triply bridged complexes [RuX(H)(cod)}2(NH2NMe2)](2; X = Cl or Br; cod = cyclo-octa-1,5-diene), containing H, X, and NH2NMe2 as bridging ligands, have been prepared from [RuH(cod)(NH2NMe2)3]A (1; A = PF6 or BPh4) and LiX in moderate yields from acetone–methanol mixtures. The mother liquors of these reactions produced [Ru3(CO)12] and [RuX(H)(PPh3)3] with CO and PPh3 respectively. Complexes (2)
    包含H,X和H的三重桥连络合物[RuX(H)(cod)} 2(NH 2 NMe 2)](2; X = Cl或Br; cod =环八-1,5-二烯)从[RuH(cod)(NH 2 NMe 2)3 ] A(1; A = PF 6或BPh 4)和LiX,以丙酮-甲醇混合物的适度产率制备了NH 2 NMe 2作为桥连配体。这些反应的母液与CO和PPh 3一起生成了[Ru 3(CO)12 ]和[RuX(H)(PPh 3)3 ]。分别。配合物(2)与一系列中性供体配体发生桥裂反应,生成[RuX(H)(cod)L 2 ] [3; L = PMePh 2,SbPh 3,AsPh 3或吡啶(py)],[RuCl(H)(PPh 3)3 ],[RuH PPh(OMe)2 } 5 ] [PF 6 ],[RuH(cod )L 3 ] +(L = 4Me-py或NCMe),和[RuCl 2(4Me-py)4 ]。讨论了配合物的红外和1
  • η<sup>3</sup>-Allyruthenium(<scp>II</scp>) complexes as intermediates in substitution and isomerization of diene ligands; the dominant role of steric effects
    作者:Terence V. Ashworth、Anthony A. Chalmers、Eric Singleton、Hester E. Swanepoel
    DOI:10.1039/c39820000214
    日期:——
    The formation of [Ru(η3-C8H13)L3]PF6 as intermediates in the conversion of [RuH(cod)L3]PF6[cod = cyclo-octa-1,5-diene, L = PMe3, P(OMe)2Ph,PMe2Ph, P(OMe)Ph2, and P(OCH2CMe3)3] into [RuHL4(solvent)]PF6[L = P(OMe)Ph2 and P(OCH2CMe3)3] and [RuHL5]PF6[L = PMe3, P(OMe)2Ph and PMe2Ph] and cyclo-octa-1,3-diene, has been shown be dependent upon the size of L.
    的[Ru(形成η 3 -C 8 ħ 13)L- 3 ] PF 6如[期RuH(COD)L的转换中间体3 ] PF 6 [COD =环辛-1,5-二烯,L = PMe 3,P(OMe)2 Ph,PMe 2 Ph,P(OMe)Ph 2和P(OCH 2 CMe 3)3 ]变成[RuHL 4(solvent)] PF 6 [L = P(OMe)Ph 2和P(OCH 2 CMe 3)3 ]和[RuHL 5 ] PF 6 [L = PMe在图3中,已经显示出P(OMe) 2 Ph和PMe 2 Ph]和环辛基-1,3-二烯取决于L的大小。
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