申请人:XiMo AG
公开号:US20140309466A1
公开(公告)日:2014-10-16
The invention relates to a method of forming an olefin from a first olefin and a second olefin in a metathesis reaction, comprising step (i):
(i) reacting the first olefin with the second olefin in the presence of a compound that catalyzes said metathesis reaction such that the molar ratio of said compound to the first or the second olefin is from 1:500 or less, and the conversion of the first or the second olefin to said olefin is at least 50%,
characterized in that as compound that catalyzes said metathesis reaction a compound of the following formula is used:
wherein M is Mo or W; R
1
is aryl, heteroaryl, alkyl, or heteroalkyl; optionally substituted; R
2
and R
3
can be the same or different and are hydrogen, alkyl, alkenyl, heteroalkyl, heteroalkenyl, aryl, or heteroaryl; optionally substituted; R
5
is alkyl, alkoxy, heteroalkyl, aryl, heteroaryl, silylalkyl, silyloxy, optionally substituted; and R
4
is a residue R
6
—X—, wherein X═O and R
6
is aryl, optionally substituted; or X═S and R
6
is aryl, optionally substituted; or X═O and R
6
is (R
7
, R
8
, R
9
)Si; wherein R
7
, R
8
, R
9
are alkyl or phenyl, optionally substituted; or X═O and R
6
is (R
10
, R
11
, R
12
)C, wherein R
10
, R
11
, R
12
are independently selected from phenyl, alkyl; optionally substituted; and to the catalysts used in the method.
本发明涉及一种从第一烯烃和第二烯烃在交换反应中形成烯烃的方法,包括步骤(i):(i)在催化所述交换反应的化合物存在下,将第一烯烃与第二烯烃反应,使所述化合物与第一或第二烯烃的摩尔比为1:500或更低,并且第一或第二烯烃转化为所述烯烃至少为50%,其中作为催化所述交换反应的化合物使用以下公式的化合物:其中M为Mo或W;R1为芳基、杂环烷基、烷基或杂烷基;可选择地取代;R2和R3可以相同也可以不同,为氢、烷基、烯基、杂烷基、杂烯基、芳基或杂环烷基;可选择地取代;R5为烷基、烷氧基、杂烷基、芳基、杂环烷基、硅烷基、硅氧基,可选择地取代;R4为残基R6—X—,其中X=O且R6为芳基,可选择地取代;或X=S且R6为芳基,可选择地取代;或X=O且R6为(R7, R8, R9)Si;其中R7、R8、R9为烷基或苯基,可选择地取代;或X=O且R6为(R10, R11, R12)C,其中R10、R11、R12独立地选自苯基、烷基;可选择地取代;以及所述方法中使用的催化剂。