作者:J. Reedijk、A.R. Siedle、R.A. Velapoldi、J.A.M. Van Hest
DOI:10.1016/s0020-1693(00)81414-0
日期:1983.1
formula M(BTAH) n X m , with M = Cu, Zn, Cd, Hg, Pd, Ti, Sn, n = 1, 2, 3, 4, X = Cl, Br and m = 2 or 4. Similar compounds of formula Cu(ligand) n X 2 (X = Cl, Br; n = 1, 2) with 5-nitrobenzotriazole and N-methylbenzotriazole, were obtained. Compounds with anionic BTA have the formulae: Cu(BTA)Cl, Cu(BTA) 1.5 (BF 4 ) 0.5 , Cu(BTA) 2 , Hg(BTA) 2 , Cu(phen) 2 (BTA) 2 , Hg(BTA)(CH 3 ), Si(BTA)(CH 3 ) 3 , Mn(BTA)(CO)
摘要研究了苯并三唑对几种过渡
金属化合物的配位
化学。中性苯并三唑(
BTAH)与
金属化合物在不同条件下的无应答反应,中性(
BTAH)
配体和阴离子,去质子化的
配体(
BTA-)都可能与
金属配位。这些化合物的通式为M(
BTAH)n X m,其中M = Cu,Zn,Cd,Hg,Pd,Ti,Sn,n = 1、2、3、4,X = Cl,Br和m = 2或4。获得具有
5-硝基苯并三唑和N-甲基苯并三唑的类似的式Cu(
配体)n X 2(X = Cl,Br; n = 1、2)的化合物。具有阴离子
BTA的化合物的分子式为:Cu(
BTA)Cl,Cu(
BTA)1.5(BF 4)0.5,Cu(
BTA)2,Hg(
BTA)2,Cu(phen)2(
BTA)2,Hg(
BTA) )(CH 3),Si(
BTA)(CH 3)3,Mn(
BTA)(CO)5。此外,还分离出一些混合化合物,即Cu 2(
BTA)2(
BTAH)(NO 3)2,Cu