Hydrido{(acylphosphine)(diphenylphosphinous acid)}rhodium(III) Complexes. Catalysts for the Homogeneous Hydrolysis of Ammonia- or Amine-Boranes under Air
作者:Virginia San Nacianceno、Lourdes Ibarlucea、Claudio Mendicute-Fierro、Antonio Rodríguez-Diéguez、José M. Seco、Itziar Zumeta、Carlos Ubide、María A. Garralda
DOI:10.1021/om500666w
日期:2014.11.10
The reaction of [RhCl(COD)]2 (COD = 1,5-cyclooctadiene) with PPh2(o-C6H4CHO) (Rh/P = 1:1) in the presence of 4-methylpyridine (4-pic) or isoquinoline (iquin) leads to hydridoacyl complexes [RhHCl(PPh2(o-C6H4CO))L2] (L = 4-pic, 1; iquin, 2). Their reaction with diphenylphosphine oxide affords neutral complexes [RhHCl(PPh2(o-C6H4CO))(PPh2O)H}L] (L = pyridine (py), 4; 4-pic, 5; iquin, 6) with trans P-ligands
[RhCl(COD)] 2(COD = 1,5-环辛二烯)与PPh 2(o -C 6 H 4 CHO)(Rh / P = 1:1)在4-甲基吡啶(4- pic)或异喹啉(iquin)生成氢酰基复合物[RhHCl(PPh 2(o -C 6 H 4 CO))L 2 ](L = 4-pic,1 ; iquin,2)。他们与二苯基氧化膦的反应提供中性络合物[RhHCl (PPh 2(oC 6 H 4 CO))(PPh 2 O)H} L](L =吡啶(py),4 ; 4-pic,5; iquin,6),由于在二苯基次膦酸的氧原子与配位酰基的氧原子之间形成了O-H-O氢键,因此反式P配体属于正式的PCP钳形配体。的反应4与螯合剂的N-供体(LL)导致吡啶和氯化,得到阳离子[RhH的(PPH的位移2(ø -C 6 ħ 4 CO))(PPH 2 O)H}(LL)] BPH 4(LL = 2,2'-联吡啶,7