Co-ordination chemistry of higher oxidation states. Part 1. Thioether complexes of osmium (IV), iridium(IV), and platinum(IV)
作者:David J. Gulliver、William Levason、Kenneth G. Smith、Michael J. Selwood、Stephen G. Murray
DOI:10.1039/dt9800001872
日期:——
Osmium(IV) dithioether complexes [OsLCl4][L = RS(CH2)2SR, RSCHCHSR, or o-C6H4(SR)2; R = Me or Ph] have been prepared from the ligands and sodium hexachloro-osmate(IV); [OsL′Br4](L′= MeS(CH2)2SMe or MeSCHCHSMe) are formed from K2[OsBr6]. Iridium(III) anions, [NMe4][IrLCl4], cis- and trans-[Ir(SMe2)2Cl4]–, [Ir(SPh2)2Cl4]–, and [Ir(SPh2)Cl5]2–, are oxidized by chlorine to the corresponding iridium(IV)
((IV)二硫醚配合物[OsLCl 4 ] [L = RS(CH 2)2 SR,RSCH CHSR或o -C 6 H 4(SR)2;R = Me或Ph]是由配体和六氯甲酸钠(IV)制得的。由K 2 [OsBr 6 ]形成[OsL'Br 4 ](L'= MeS(CH 2)2 SMe或MeSCH CHSMe)。铱(III)阴离子,[NMe 4 ] [IrLCl 4 ],顺式和反式-[Ir(SMe 2)2 Cl 4 ] –,[Ir(SPh 2) 2 Cl 4 ] –和[Ir(SPh 2)Cl 5 ] 2 –被氯氧化成相应的铱( IV)络合物。[PtLX 2 ]的卤素氧化会产生[PtLX 4 ](X = Cl或Br)和两个不稳定的络合物[PtL''l 4 ] [L''= MeS(CH 2) n SMe, n = 2或3]。尝试制备Ru IV,Rh IV,Pd IV,Co III的硫醚配合物和Ni