The reaction of an N-acyliminium ion with an alkyl iodide and hexabutyldistannane took place to give the alkylation product. A mechanism involving the addition of an alkyl radical to an N-acyliminium ion to produce the corresponding radical cation has been suggested.
N-酰基胺离子与烷基
碘和六丁基
二锡烷发生反应,得到烷基化产物。已经提出了涉及将烷基自由基加成到 N-酰基胺离子以产生相应自由基阳离子的机制。